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x^2-1850x+180000=0
a = 1; b = -1850; c = +180000;
Δ = b2-4ac
Δ = -18502-4·1·180000
Δ = 2702500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2702500}=\sqrt{2500*1081}=\sqrt{2500}*\sqrt{1081}=50\sqrt{1081}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1850)-50\sqrt{1081}}{2*1}=\frac{1850-50\sqrt{1081}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1850)+50\sqrt{1081}}{2*1}=\frac{1850+50\sqrt{1081}}{2} $
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